Difference between revisions of "Titration of an Acid Final Project Lab"
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(write it from paper) |
(→Results: fix wording) |
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*10.20ml Acid * ?M Acid = 10.11mL base * .1012M Base | *10.20ml Acid * ?M Acid = 10.11mL base * .1012M Base | ||
*10.20mL * ?M Acid = 1.023132 mlM base | *10.20mL * ?M Acid = 1.023132 mlM base | ||
− | * | + | *(divide both side by 10.20ml) |
*'''.1003M = C<sub>A</sub>''' | *'''.1003M = C<sub>A</sub>''' | ||
==Formula== | ==Formula== | ||
NaOH<sub>(aq)</sub>+CH<sub>3</sub>COOH<sub>(aq)</sub> -> Na<sub>(aq)</sub> + H<sub>2</sub>O<sub>(l)</sub>+CH<sub>3</sub>COO<sub>(aq)</sub> | NaOH<sub>(aq)</sub>+CH<sub>3</sub>COOH<sub>(aq)</sub> -> Na<sub>(aq)</sub> + H<sub>2</sub>O<sub>(l)</sub>+CH<sub>3</sub>COO<sub>(aq)</sub> |
Revision as of 12:08, 5 June 2007
Titration of an Unknown Acid Final Project Lab for Chemistry
Contents |
Purpose
To use the concentration of a known base to determine the concentration of an unknown acid
Directions
Titrate to endpoint a sodium hydroxide solution with a acetic acid solution of an unknown concentration. Use phenolphthalein as an indicator. Start with 10mL of acid.
Results
- Using Acid "B" at .1012M concentration
- Filled up both burettes to 0mL
Titrated with 10.20mL of Acid "B" amd 10.11mL Base
- VA*CA=VB*CB
- 10.20ml Acid * ?M Acid = 10.11mL base * .1012M Base
- 10.20mL * ?M Acid = 1.023132 mlM base
- (divide both side by 10.20ml)
- .1003M = CA
Formula
NaOH(aq)+CH3COOH(aq) -> Na(aq) + H2O(l)+CH3COO(aq)