Difference between revisions of "Sticky Gum Problem POW"

From ThePlaz.com

Jump to: navigation, search
(Solution (Ultimate Goal))
(imp takedown)
 
(One intermediate revision by one user not shown)
Line 1: Line 1:
 
<big>'''[[IAG 1H]] [[POW]] <nowiki>#</nowiki> 4: A Sticky Gum Problem'''</big>
 
<big>'''[[IAG 1H]] [[POW]] <nowiki>#</nowiki> 4: A Sticky Gum Problem'''</big>
 
+
{{IMP Takedown}}
{{Word|Image:A_Sticky_Gum_Problem.doc}}
+
{{PDF|Image:A_Sticky_Gum_Problem.pdf}}
+
 
+
==Problem Statement==
+
Not necessary to do.
+
 
+
==Process and answers to problems 1,2 & 3==
+
1. (2 colors, 2 people) Ms. Hernandez can only spend 3 cents, because on her first cent, she can get a white or a red gumball.  On her second turn, she can also only get a red or  white gumball.  Now she can only have 4 combinations:  Red and White Gumballs;  Red and Red Gumballs;  White and White Gumballs;  White and Red Gumballs.  With 2 of these possible combinations, she already has her goal of having 2 of the same color gumballs.  On her third try, she gets another red or white gumball.  Whatever the color, she already has one of them, which makes 2 of the same color.
+
 
+
[[Image:Sticky Gum Problem Diagram 1.png]]
+
+
2.  (3 colors, 2 people) Ms. Hernandez now finds a machine that has 3 colors in it.  The most that she will need to spend to get 2 of the same color is 4 cents.  To find all of the possible strategies, look at the chart:
+
 
+
[[Image:Sticky Gum Problem Diagram 2.png]]
+
+
3. (3 colors, 3 people)  It will take 7 cents to get 3 of the same color, as there are 108 possible combinations.  Here is a chart showing the 1st third of them (if the first color is red)
+
 
+
[[Image:Sticky Gum Problem Diagram 3.png]]
+
 
+
I will now make a chart showing my findings so far.
+
 
+
{|border="2" cellspacing="0" cellpadding="4"
+
|align = "center"|<u>'''Colors'''</u>
+
|align = "center"|<u>'''Kids'''</u>
+
|align = "center"|<u>'''Max Spend'''</u>
+
|align = "center"|<u>'''Combos'''</u>
+
|-
+
|align = "center"|2
+
|align = "center"|2
+
|align = "center"|3 cents
+
|align = "center"|6
+
|-
+
|align = "center"|3
+
|align = "center"|2
+
|align = "center"|4 cents
+
|align = "center"|33
+
|-
+
|align = "center"|3
+
|align = "center"|3
+
|align = "center"|7 cents
+
|align = "center"|108
+
|-
+
|}
+
 
+
Now I will make up some problems to help fill in the chart some more.
+
 
+
4. (2 colors, 3 kids)  This chart shows the first half of needing 3 of the same color, with only 2 colors.  It will take 5 cents and there are 16 combinations.
+
 
+
[[Image:Sticky Gum Problem Diagram 4.png]]
+
+
5. (2 colors, 4 kids)  This shows the first half of getting 4 of 1 color and having 2 colors.  You need 7 cents, and there are 68 combos.
+
 
+
[[Image:Sticky Gum Problem Diagram 5.png]]
+
+
6. (4 colors, 2 kids) This shows the first quarter of the chart, when you need 2 of the same, and there are 4 colors.  You need 5 turns to get 4 of the same, and there are 200 combinations.
+
 
+
[[Image:Sticky Gum Problem Diagram 6.png]]
+
 
+
==Solution (Ultimate Goal)==
+
 
+
Let me make another chart.  I have included 1 color and 1 kid for comparison.
+
 
+
{|border="2" cellspacing="0" cellpadding="4"
+
|align = "center"|<u>'''Colors'''</u>
+
|align = "center"|<u>'''Kids'''</u>
+
|align = "center"|<u>'''Max Spend'''</u>
+
|align = "center"|<u>'''Combos'''</u>
+
|-
+
|align = "center"|<font color="#999999">1</font>
+
|align = "center"|<font color="#999999">1</font>
+
|align = "center"|<font color="#999999">1</font>
+
|align = "center"|<font color="#999999">1</font>
+
|-
+
|align = "center"|<font color="#999999">1</font>
+
|align = "center"|<font color="#999999">2</font>
+
|align = "center"|<font color="#999999">2</font>
+
|align = "center"|<font color="#999999">1</font>
+
|-
+
|align = "center"|<font color="#999999">2</font>
+
|align = "center"|<font color="#999999">1</font>
+
|align = "center"|<font color="#999999">1</font>
+
|align = "center"|<font color="#999999">2</font>
+
|-
+
|align = "center"|2
+
|align = "center"|2
+
|align = "center"|3 cents
+
|align = "center"|6
+
|-
+
|align = "center"|2
+
|align = "center"|3
+
|align = "center"|5
+
|align = "center"|16
+
|-
+
|align = "center"|2
+
|align = "center"|4
+
|align = "center"|7
+
|align = "center"|68
+
|-
+
|align = "center"|3
+
|align = "center"|2
+
|align = "center"|4 cents
+
|align = "center"|33
+
|-
+
|align = "center"|3
+
|align = "center"|3
+
|align = "center"|7 cents
+
|align = "center"|108
+
|-
+
|align = "center"|4
+
|align = "center"|2
+
|align = "center"|5
+
|align = "center"|200
+
|-
+
|}
+
 
+
 
+
Overall, I have found that number of colors is ultimately responsible for combinations, but the number of kids is ultimately responsible for the maximum, you spend.  Here is something interesting:
+
 
+
{|border="2" cellspacing="0" cellpadding="4"
+
|align = "center"|<u>'''Colors'''</u>
+
|align = "center"|<u>'''Kids'''</u>
+
|align = "center"|<u>'''Max Spend'''</u>
+
|-
+
|align = "center"|2
+
|align = "center" rowspan = "3"|<big>2</big>
+
|align = "center"|3
+
|-
+
|align = "center"|3
+
|align = "center"|4
+
|-
+
|align = "center"|4
+
|align = "center"|5
+
|-
+
|}
+
 
+
When you have 2 kids max spend is equal to number of colors plus 1.  What about having 3 kids:
+
 
+
 
+
{|border="2" cellspacing="0" cellpadding="4"
+
|align = "center"|<u>'''Colors'''</u>
+
|align = "center"|<u>'''Kids'''</u>
+
|align = "center"|<u>'''Max Spend'''</u>
+
|-
+
|align = "center"|2
+
|align = "center" rowspan = "2"|<big>3</big>
+
|align = "center"|5
+
|-
+
|align = "center"|3
+
|align = "center"|7
+
|-
+
|}
+
 
+
This chart shows so far that when you add a color, the max that you spend, goes down.
+
 
+
When you start adding a color, the number of cents goes down; when you then keep adding people, the number of cents goes up. 
+
 
+
I have also found that this works:
+
<big><nowiki>[</nowiki>(<nowiki>#</nowiki> of colors) <nowiki>*</nowiki> (<nowiki>#</nowiki> of kids)<nowiki>]</nowiki> - <nowiki>[</nowiki>(<nowiki>#</nowiki> of colors) + 1<nowiki>]</nowiki></big>
+
 
+
==Extension==
+
Not necessary to do.
+
 
+
==Evaluation==
+
Not necessary to do.
+
  
 
[[Category:IAG 1H]]
 
[[Category:IAG 1H]]
 
[[Category:POW]]
 
[[Category:POW]]

Latest revision as of 16:19, 11 December 2008

IAG 1H POW # 4: A Sticky Gum Problem

Nuvola apps important.png IMP Takedown

I was asked to take down POW solutions. Remember it's best to think about how to solve the problems on your own.