Difference between revisions of "Titration of an Acid Final Project Lab"

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(write it from paper)
 
(Results: fix wording)
Line 17: Line 17:
 
*10.20ml Acid * ?M Acid = 10.11mL base * .1012M Base
 
*10.20ml Acid * ?M Acid = 10.11mL base * .1012M Base
 
*10.20mL * ?M Acid = 1.023132 mlM base
 
*10.20mL * ?M Acid = 1.023132 mlM base
*/10.20ml
+
*(divide both side by 10.20ml)
 
*'''.1003M = C<sub>A</sub>'''
 
*'''.1003M = C<sub>A</sub>'''
  
 
==Formula==
 
==Formula==
 
NaOH<sub>(aq)</sub>+CH<sub>3</sub>COOH<sub>(aq)</sub> -> Na<sub>(aq)</sub> + H<sub>2</sub>O<sub>(l)</sub>+CH<sub>3</sub>COO<sub>(aq)</sub>
 
NaOH<sub>(aq)</sub>+CH<sub>3</sub>COOH<sub>(aq)</sub> -> Na<sub>(aq)</sub> + H<sub>2</sub>O<sub>(l)</sub>+CH<sub>3</sub>COO<sub>(aq)</sub>

Revision as of 12:08, 5 June 2007

Titration of an Unknown Acid Final Project Lab for Chemistry

Contents

Purpose

To use the concentration of a known base to determine the concentration of an unknown acid

Directions

Titrate to endpoint a sodium hydroxide solution with a acetic acid solution of an unknown concentration. Use phenolphthalein as an indicator. Start with 10mL of acid.

Results

  • Using Acid "B" at .1012M concentration
  • Filled up both burettes to 0mL

Titrated with 10.20mL of Acid "B" amd 10.11mL Base

  • VA*CA=VB*CB
  • 10.20ml Acid * ?M Acid = 10.11mL base * .1012M Base
  • 10.20mL * ?M Acid = 1.023132 mlM base
  • (divide both side by 10.20ml)
  • .1003M = CA

Formula

NaOH(aq)+CH3COOH(aq) -> Na(aq) + H2O(l)+CH3COO(aq)